• you old curmudgeon

    From Lane W@3:633/10 to All on Tuesday, September 15, 2026 11:11:28
    Here's a blatant hallucination I'd like you to look at. If requested, I
    will provide the prompt. Due to its ability to find the error it was experiencing, I may forgive good old Google AI Overview. We swapped
    riddles a while back and it caught me off guard on one. It's a wash? At
    least I think it found its error. You be the judge:

    The white side that is not touching a black side on its edge is the
    opposite side (the face directly parallel to the other black side,
    meaning the two black sides are opposite each other).
    On a cube:
    A cube has 6 faces.
    If 2 faces are painted black and 4 are painted white, the 2 black faces
    are either adjacent (sharing an edge) or opposite (parallel with no
    shared edges).
    If the two black sides share an edge, every single one of the 4 white
    sides touches at least one of the black sides along an edge.
    If the two black sides are opposite each other, they do not share any
    edges. In this specific configuration, the four white sides form a band
    around the middle connecting them, and none of the white sides are
    opposite each other?wait, if two black sides are opposite, the other 4
    sides are white and all touch both black sides.
    Re-evaluating the premise: If two sides are black and 4 are white, and
    one specific white side does not touch a black side on its edge, the two
    black sides must be adjacent (sharing an edge). The white side that does
    not touch either black side is the face opposite to the edge shared by
    the two black sides?specifically, the single white face that is opposite
    the corner/edge where the two black faces meet. Wait, let's trace an
    adjacent pair: faces 1 and 2 are black and share an edge \(E\). Face 3
    is opposite face 1, face 4 is opposite face 2. Face 5 is opposite...
    wait. Let's list adjacent faces: Top (1) and Front (2) are black,
    sharing edge TF. Bottom (6) is opposite Top (1), and Back (5) is
    opposite Front (2). Left (3) and Right (4) are the other two sides,
    adjacent to both Top and Front. Therefore, Left and Right both touch the
    Top and Front black faces. Bottom (6) touches Back, Left, Right, Front
    (wait, Bottom touches Front, Back, Left, Right edges, so Bottom touches
    Front black face!). Back (5) touches Top, Bottom, Left, Right, and
    Front? No, Back touches Top, Bottom, Left, Right. Does Back touch Top
    and Front? Back shares an edge with Top! So Back touches the Top black
    face. What face doesn't touch any black face? If Top and Front are black (sharing an edge):
    Left touches Top and Front.
    Right touches Top and Front.
    Back touches Top (and Bottom, Left, Right).
    Bottom touches Front (and Back, Left, Right).
    Every single one of the 4 white sides touches either Top or Front (or
    both) because Top and Front share an edge and the other 4 faces all
    share an edge with either Top or Front!
    Let's re-verify: A cube has 6 faces. Every face shares edges with 4
    adjacent faces and is parallel to 1 opposite face. If 2 faces are black (\(B_1, B_2\)) and they are adjacent, they share 1 edge. The remaining 4
    faces are white. Each of the 4 white faces shares edges with 4 faces.
    Since \(B_{1}\) and \(B_{2}\) are adjacent, they take up 1 neighbor spot
    for each other, and they are neighbors to 8 faces total? No, each face
    has 4 neighbors. \(B_{1}\)'s neighbors are 4 faces (let's say \(W_a,
    W_b, W_c\) and \(B_{2}\)). \(B_{2}\)'s neighbors are \(B_1, W_a, W_b,
    W_d\). Thus, the white neighbors of the black faces are \(W_a, W_b, W_c,
    W_d\) ? wait, that's only 4 faces total! The total number of faces is 6.
    Two are black. Four are white. Since the two black faces share an edge,
    they are neighbors to each other and to some set of white faces. Each
    face has 4 edges/neighbors. Two black faces share 1 edge with each
    other. That leaves \(2 \times 4 - 2 = 6\) edge slots available to
    connect with white faces. Since there are 4 white faces, and each white
    face can touch one or both black faces, let's check: do all 4 white
    faces touch a black face? Yes, because every white face is adjacent to
    at least one of the black faces.
    Wait, what if the question implies the two black sides are opposite each other? If two black sides are opposite, they touch 4 white sides. Each
    of the 4 white sides touches both black sides on two opposite edges! If
    the two black sides are adjacent, do all 4 white sides touch a black
    side? Yes. Is there any white side not touching a black side? None,
    unless the definition of "touching a black side on its edge" means
    something specific, or the two black sides are separated by a white side (i.e., non-adjacent, but on a cube all non-identical non-adjacent faces
    are opposite). Wait! Can two faces on a cube share only a vertex? Faces
    on a cube either share an edge (adjacent) or are parallel (opposite).
    They never share just a vertex. Therefore, every white face shares an
    edge with at least one adjacent face, and if two faces are black and
    adjacent, every white face is adjacent to at least one of them. Wait, if
    two black faces are adjacent, do they touch all 4 white faces? Let's
    check: Top and Bottom are opposite. Top and Front are adjacent. If Top
    is black and Bottom is black (opposite), the 4 side faces (Front, Back,
    Left, Right) are white, and every single one of them touches both Top
    and Bottom black faces on its top and bottom edges! If Top is black and
    Front is black (adjacent), the remaining faces are Back, Bottom, Left,
    Right. Back is opposite Front (so Back does not touch Front), but Back
    is adjacent to Top! So Back touches Top. Bottom is opposite Top (does
    not touch Top), but Bottom is adjacent to Front! So Bottom touches
    Front. Left is adjacent to both Top and Front. Right is adjacent to both
    Top and Front. Thus, every white face touches at least one black face.

    --
    Everything I work for
    Everything I long for is always just too far
    Everything I hope for never comes to be
    Everything I bleed for burns a scar on me
    Everything I fight for leaves a bitter taste
    Everything I cry for laughs into my face
    Everything I scream for barely knows my name
    Everything I'd die for will die just the same

    Everything I worked for
    Everything I longed for was always just too far
    Everything I hoped for never came to be
    Everything I bled for burned a scar on me
    Everything I fought for left a bitter taste
    Everything I cried for laughed into my face
    Everything I screamed for barely knew my name
    Everything I died for died just the same

    --- PyGate Linux v1.5.19
    * Origin: Dragon's Lair, PyGate NNTP<>Fido Gate (3:633/10)
  • From JM@3:633/10 to All on Wednesday, September 16, 2026 02:37:36
    On Tue, 15 Sep 2026 11:11:28 -0600, Lane W <cactus_DAC@yahoo.com>
    wrote:

    ?

    "uh-huh"

    --- PyGate Linux v1.5.19
    * Origin: Dragon's Lair, PyGate NNTP<>Fido Gate (3:633/10)